Tuesday, August 9, 2011

Chemistry Question!!!!!!!!!!! Please help!!!!!!!!!!! instant 10 points?

A 50.0 mL sample of a 1.00 M solution of copper (II) nitrate (187.57 g/mol) is reacted with sodium hydroxide to give a precipitate of copper (II) hydroxide. In the space below, calculate the m of copper (II) hydroxide (97.56 g/mol) that will be formed in this reaction. Calculate your answer in units of grams, but do not enter units, commas or exponential notation in the blank.

No comments:

Post a Comment